Base | Representation |
---|---|
bin | 10100101110100000110… |
… | …111010110101100110111 |
3 | 12001011110012220022202211 |
4 | 110232200313112230313 |
5 | 141314013224243224 |
6 | 3010155104114251 |
7 | 204622205040631 |
oct | 24564067265467 |
9 | 5034405808684 |
10 | 1424333040439 |
11 | 4aa068961771 |
12 | 1b0066305987 |
13 | a4410bcbb5a |
14 | 4cd1c179a51 |
15 | 270b44d9894 |
hex | 14ba0dd6b37 |
1424333040439 has 2 divisors, whose sum is σ = 1424333040440. Its totient is φ = 1424333040438.
The previous prime is 1424333040437. The next prime is 1424333040521. The reversal of 1424333040439 is 9340403334241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1424333040439 - 21 = 1424333040437 is a prime.
It is a super-2 number, since 2×14243330404392 (a number of 25 digits) contains 22 as substring.
Together with 1424333040437, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1424333040433) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 712166520219 + 712166520220.
It is an arithmetic number, because the mean of its divisors is an integer number (712166520220).
Almost surely, 21424333040439 is an apocalyptic number.
1424333040439 is a deficient number, since it is larger than the sum of its proper divisors (1).
1424333040439 is an equidigital number, since it uses as much as digits as its factorization.
1424333040439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 373248, while the sum is 40.
The spelling of 1424333040439 in words is "one trillion, four hundred twenty-four billion, three hundred thirty-three million, forty thousand, four hundred thirty-nine".
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