Base | Representation |
---|---|
bin | 1100111101001001001001… |
… | …0101000010111101111011 |
3 | 1212102202201100000122210222 |
4 | 3033102102111002331323 |
5 | 3331340333013404001 |
6 | 50143510304530255 |
7 | 3000064431600341 |
oct | 317222225027573 |
9 | 55382640018728 |
10 | 14244566544251 |
11 | 45a20a550613a |
12 | 172083862098b |
13 | 7c434542aa64 |
14 | 3736253c9991 |
15 | 19a801bde61b |
hex | cf492542f7b |
14244566544251 has 2 divisors, whose sum is σ = 14244566544252. Its totient is φ = 14244566544250.
The previous prime is 14244566544227. The next prime is 14244566544253. The reversal of 14244566544251 is 15244566544241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14244566544251 - 210 = 14244566543227 is a prime.
Together with 14244566544253, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 14244566544193 and 14244566544202.
It is not a weakly prime, because it can be changed into another prime (14244566544253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7122283272125 + 7122283272126.
It is an arithmetic number, because the mean of its divisors is an integer number (7122283272126).
Almost surely, 214244566544251 is an apocalyptic number.
14244566544251 is a deficient number, since it is larger than the sum of its proper divisors (1).
14244566544251 is an equidigital number, since it uses as much as digits as its factorization.
14244566544251 is an evil number, because the sum of its binary digits is even.
The product of its digits is 18432000, while the sum is 53.
The spelling of 14244566544251 in words is "fourteen trillion, two hundred forty-four billion, five hundred sixty-six million, five hundred forty-four thousand, two hundred fifty-one".
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