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14250230537 is a prime number
BaseRepresentation
bin11010100010110000…
…10100001100001001
31100210010022201100012
431101120110030021
5213141024334122
610314011521305
71013063650424
oct152130241411
940703281305
1014250230537
11605297a134
122918459235
13146140249a
149928129bb
155860b07e2
hex351614309

14250230537 has 2 divisors, whose sum is σ = 14250230538. Its totient is φ = 14250230536.

The previous prime is 14250230531. The next prime is 14250230539. The reversal of 14250230537 is 73503205241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11316491641 + 2933738896 = 106379^2 + 54164^2 .

It is a cyclic number.

It is not a de Polignac number, because 14250230537 - 216 = 14250165001 is a prime.

Together with 14250230539, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14250230531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7125115268 + 7125115269.

It is an arithmetic number, because the mean of its divisors is an integer number (7125115269).

Almost surely, 214250230537 is an apocalyptic number.

It is an amenable number.

14250230537 is a deficient number, since it is larger than the sum of its proper divisors (1).

14250230537 is an equidigital number, since it uses as much as digits as its factorization.

14250230537 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25200, while the sum is 32.

Adding to 14250230537 its reverse (73503205241), we get a palindrome (87753435778).

The spelling of 14250230537 in words is "fourteen billion, two hundred fifty million, two hundred thirty thousand, five hundred thirty-seven".