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142531312873 is a prime number
BaseRepresentation
bin1000010010111110000…
…1110011110011101001
3111121220020210220012211
42010233201303303221
54313401004002443
6145251124405121
713204026112135
oct2045741636351
9447806726184
10142531312873
11554a1234a54
12237595467a1
1310596135b71
146c818b03c5
153a9308519d
hex212f873ce9

142531312873 has 2 divisors, whose sum is σ = 142531312874. Its totient is φ = 142531312872.

The previous prime is 142531312871. The next prime is 142531312879. The reversal of 142531312873 is 378213135241.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97920803929 + 44610508944 = 312923^2 + 211212^2 .

It is a cyclic number.

It is not a de Polignac number, because 142531312873 - 21 = 142531312871 is a prime.

Together with 142531312871, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (142531312871) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71265656436 + 71265656437.

It is an arithmetic number, because the mean of its divisors is an integer number (71265656437).

Almost surely, 2142531312873 is an apocalyptic number.

It is an amenable number.

142531312873 is a deficient number, since it is larger than the sum of its proper divisors (1).

142531312873 is an equidigital number, since it uses as much as digits as its factorization.

142531312873 is an evil number, because the sum of its binary digits is even.

The product of its digits is 120960, while the sum is 40.

The spelling of 142531312873 in words is "one hundred forty-two billion, five hundred thirty-one million, three hundred twelve thousand, eight hundred seventy-three".