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142633631260097 is a prime number
BaseRepresentation
bin100000011011100101111010…
…111011001001110111000001
3200201000122100000002110211022
4200123211322323021313001
5122143402134100310342
61223204552520555225
742020640230450135
oct4033457273116701
9621018300073738
10142633631260097
11414a164643905a
1213bb742a622b15
1361783a83a0b73
14273170c8353c5
151175364b499d2
hex81b97aec9dc1

142633631260097 has 2 divisors, whose sum is σ = 142633631260098. Its totient is φ = 142633631260096.

The previous prime is 142633631260051. The next prime is 142633631260103. The reversal of 142633631260097 is 790062136336241.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85789812273841 + 56843818986256 = 9262279^2 + 7539484^2 .

It is a cyclic number.

It is not a de Polignac number, because 142633631260097 - 28 = 142633631259841 is a prime.

It is a super-2 number, since 2×1426336312600972 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (142633631260297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71316815630048 + 71316815630049.

It is an arithmetic number, because the mean of its divisors is an integer number (71316815630049).

Almost surely, 2142633631260097 is an apocalyptic number.

It is an amenable number.

142633631260097 is a deficient number, since it is larger than the sum of its proper divisors (1).

142633631260097 is an equidigital number, since it uses as much as digits as its factorization.

142633631260097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5878656, while the sum is 53.

The spelling of 142633631260097 in words is "one hundred forty-two trillion, six hundred thirty-three billion, six hundred thirty-one million, two hundred sixty thousand, ninety-seven".