Base | Representation |
---|---|
bin | 10100110000100101100… |
… | …110111101010110001101 |
3 | 12001101012102112021122012 |
4 | 110300211212331112031 |
5 | 141333043342041023 |
6 | 3011204102031005 |
7 | 205031326610651 |
oct | 24604546752615 |
9 | 5041172467565 |
10 | 1426560112013 |
11 | 500000aa1593 |
12 | 1b0588118465 |
13 | a46a741b59a |
14 | 4d08dc62a61 |
15 | 27194ca2978 |
hex | 14c259bd58d |
1426560112013 has 2 divisors, whose sum is σ = 1426560112014. Its totient is φ = 1426560112012.
The previous prime is 1426560111959. The next prime is 1426560112069. The reversal of 1426560112013 is 3102110656241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1037979928969 + 388580183044 = 1018813^2 + 623362^2 .
It is a cyclic number.
It is not a de Polignac number, because 1426560112013 - 214 = 1426560095629 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1426560112073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 713280056006 + 713280056007.
It is an arithmetic number, because the mean of its divisors is an integer number (713280056007).
Almost surely, 21426560112013 is an apocalyptic number.
It is an amenable number.
1426560112013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1426560112013 is an equidigital number, since it uses as much as digits as its factorization.
1426560112013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 32.
Adding to 1426560112013 its reverse (3102110656241), we get a palindrome (4528670768254).
The spelling of 1426560112013 in words is "one trillion, four hundred twenty-six billion, five hundred sixty million, one hundred twelve thousand, thirteen".
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