Base | Representation |
---|---|
bin | 10100110001010100000… |
… | …110111110000100010111 |
3 | 12001110012210111200022211 |
4 | 110301110012332010113 |
5 | 141341143101134021 |
6 | 3011413331134251 |
7 | 205056551663542 |
oct | 24612406760427 |
9 | 5043183450284 |
10 | 1427340255511 |
11 | 5003713aa985 |
12 | 1b0765444387 |
13 | a479cc3b461 |
14 | 4d1256dd859 |
15 | 271dd5063e1 |
hex | 14c541be117 |
1427340255511 has 2 divisors, whose sum is σ = 1427340255512. Its totient is φ = 1427340255510.
The previous prime is 1427340255487. The next prime is 1427340255527. The reversal of 1427340255511 is 1155520437241.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1427340255511 - 29 = 1427340254999 is a prime.
It is a super-2 number, since 2×14273402555112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1427340252511) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 713670127755 + 713670127756.
It is an arithmetic number, because the mean of its divisors is an integer number (713670127756).
Almost surely, 21427340255511 is an apocalyptic number.
1427340255511 is a deficient number, since it is larger than the sum of its proper divisors (1).
1427340255511 is an equidigital number, since it uses as much as digits as its factorization.
1427340255511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168000, while the sum is 40.
The spelling of 1427340255511 in words is "one trillion, four hundred twenty-seven billion, three hundred forty million, two hundred fifty-five thousand, five hundred eleven".
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