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14300021111 is a prime number
BaseRepresentation
bin11010101000101100…
…10000000101110111
31100220121000100011112
431110112100011313
5213241301133421
610322551025235
71014240113435
oct152426200567
940817010145
1014300021111
116078a97572
12293106b21b
13146b81646c
14999293d55
1558a64845b
hex354590177

14300021111 has 2 divisors, whose sum is σ = 14300021112. Its totient is φ = 14300021110.

The previous prime is 14300021069. The next prime is 14300021161. The reversal of 14300021111 is 11112000341.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14300021111 is a prime.

It is a super-3 number, since 3×143000211113 (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14300021161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7150010555 + 7150010556.

It is an arithmetic number, because the mean of its divisors is an integer number (7150010556).

Almost surely, 214300021111 is an apocalyptic number.

14300021111 is a deficient number, since it is larger than the sum of its proper divisors (1).

14300021111 is an equidigital number, since it uses as much as digits as its factorization.

14300021111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 14300021111 its reverse (11112000341), we get a palindrome (25412021452).

The spelling of 14300021111 in words is "fourteen billion, three hundred million, twenty-one thousand, one hundred eleven".