Base | Representation |
---|---|
bin | 11010101000101100… |
… | …10000000101110111 |
3 | 1100220121000100011112 |
4 | 31110112100011313 |
5 | 213241301133421 |
6 | 10322551025235 |
7 | 1014240113435 |
oct | 152426200567 |
9 | 40817010145 |
10 | 14300021111 |
11 | 6078a97572 |
12 | 293106b21b |
13 | 146b81646c |
14 | 999293d55 |
15 | 58a64845b |
hex | 354590177 |
14300021111 has 2 divisors, whose sum is σ = 14300021112. Its totient is φ = 14300021110.
The previous prime is 14300021069. The next prime is 14300021161. The reversal of 14300021111 is 11112000341.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14300021111 is a prime.
It is a super-3 number, since 3×143000211113 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14300021161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7150010555 + 7150010556.
It is an arithmetic number, because the mean of its divisors is an integer number (7150010556).
Almost surely, 214300021111 is an apocalyptic number.
14300021111 is a deficient number, since it is larger than the sum of its proper divisors (1).
14300021111 is an equidigital number, since it uses as much as digits as its factorization.
14300021111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 14300021111 its reverse (11112000341), we get a palindrome (25412021452).
The spelling of 14300021111 in words is "fourteen billion, three hundred million, twenty-one thousand, one hundred eleven".
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