Base | Representation |
---|---|
bin | 100000100001001110001000… |
… | …001010011101000011101111 |
3 | 200202101121122121112002211112 |
4 | 200201032020022131003233 |
5 | 122221221240002300333 |
6 | 1224102355342342235 |
7 | 42060611564246321 |
oct | 4041161012350357 |
9 | 622347577462745 |
10 | 143020400431343 |
11 | 4163067a566a36 |
12 | 1405a38a88a97b |
13 | 61a59c587ac46 |
14 | 274631d743611 |
15 | 118044ebe7948 |
hex | 82138829d0ef |
143020400431343 has 2 divisors, whose sum is σ = 143020400431344. Its totient is φ = 143020400431342.
The previous prime is 143020400431339. The next prime is 143020400431357. The reversal of 143020400431343 is 343134004020341.
It is a weak prime.
It is an emirp because it is prime and its reverse (343134004020341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 143020400431343 - 22 = 143020400431339 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143020400431243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71510200215671 + 71510200215672.
It is an arithmetic number, because the mean of its divisors is an integer number (71510200215672).
Almost surely, 2143020400431343 is an apocalyptic number.
143020400431343 is a deficient number, since it is larger than the sum of its proper divisors (1).
143020400431343 is an equidigital number, since it uses as much as digits as its factorization.
143020400431343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 143020400431343 its reverse (343134004020341), we get a palindrome (486154404451684).
The spelling of 143020400431343 in words is "one hundred forty-three trillion, twenty billion, four hundred million, four hundred thirty-one thousand, three hundred forty-three".
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