Base | Representation |
---|---|
bin | 1101000000100011101100… |
… | …0000101110000101101111 |
3 | 1212122101010202210220121011 |
4 | 3100020323000232011233 |
5 | 3333321004132441312 |
6 | 50230451430450051 |
7 | 3004242254460652 |
oct | 320107300560557 |
9 | 55571122726534 |
10 | 14303231140207 |
11 | 4614a6a104399 |
12 | 173008b203927 |
13 | 7c9a34305329 |
14 | 3763cc783899 |
15 | 19c0d70abda7 |
hex | d023b02e16f |
14303231140207 has 2 divisors, whose sum is σ = 14303231140208. Its totient is φ = 14303231140206.
The previous prime is 14303231140171. The next prime is 14303231140243. The reversal of 14303231140207 is 70204113230341.
It is a balanced prime because it is at equal distance from previous prime (14303231140171) and next prime (14303231140243).
It is an emirp because it is prime and its reverse (70204113230341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14303231140207 - 211 = 14303231138159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14303231140307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7151615570103 + 7151615570104.
It is an arithmetic number, because the mean of its divisors is an integer number (7151615570104).
Almost surely, 214303231140207 is an apocalyptic number.
14303231140207 is a deficient number, since it is larger than the sum of its proper divisors (1).
14303231140207 is an equidigital number, since it uses as much as digits as its factorization.
14303231140207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 14303231140207 its reverse (70204113230341), we get a palindrome (84507344370548).
The spelling of 14303231140207 in words is "fourteen trillion, three hundred three billion, two hundred thirty-one million, one hundred forty thousand, two hundred seven".
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