Base | Representation |
---|---|
bin | 100000100001011010010000… |
… | …011000000110111100100111 |
3 | 200202102212021012000202120002 |
4 | 200201122100120012330213 |
5 | 122221424422310133112 |
6 | 1224112351504131515 |
7 | 42061552364334065 |
oct | 4041322030067447 |
9 | 622385235022502 |
10 | 143033423130407 |
11 | 41636152535547 |
12 | 14060a04006b9b |
13 | 61a6cbc869734 |
14 | 2746bd70db035 |
15 | 11809631301c2 |
hex | 821690606f27 |
143033423130407 has 2 divisors, whose sum is σ = 143033423130408. Its totient is φ = 143033423130406.
The previous prime is 143033423130401. The next prime is 143033423130449. The reversal of 143033423130407 is 704031324330341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 143033423130407 - 230 = 143032349388583 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143033423130401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71516711565203 + 71516711565204.
It is an arithmetic number, because the mean of its divisors is an integer number (71516711565204).
Almost surely, 2143033423130407 is an apocalyptic number.
143033423130407 is a deficient number, since it is larger than the sum of its proper divisors (1).
143033423130407 is an equidigital number, since it uses as much as digits as its factorization.
143033423130407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 217728, while the sum is 38.
Adding to 143033423130407 its reverse (704031324330341), we get a palindrome (847064747460748).
The spelling of 143033423130407 in words is "one hundred forty-three trillion, thirty-three billion, four hundred twenty-three million, one hundred thirty thousand, four hundred seven".
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