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1430665813919 is a prime number
BaseRepresentation
bin10100110100011010010…
…100111101111110011111
312001202210120010112211202
4110310122110331332133
5141420000422021134
63013123325310115
7205235142525236
oct24643224757637
95052716115752
101430665813919
11501818611161
121b133310533b
13a4bacbcbbb4
144d35d24db1d
1527335456d7e
hex14d1a53df9f

1430665813919 has 2 divisors, whose sum is σ = 1430665813920. Its totient is φ = 1430665813918.

The previous prime is 1430665813909. The next prime is 1430665813921. The reversal of 1430665813919 is 9193185660341.

It is a strong prime.

It is an emirp because it is prime and its reverse (9193185660341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1430665813919 - 228 = 1430397378463 is a prime.

It is a super-2 number, since 2×14306658139192 (a number of 25 digits) contains 22 as substring.

Together with 1430665813921, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1430665813909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715332906959 + 715332906960.

It is an arithmetic number, because the mean of its divisors is an integer number (715332906960).

Almost surely, 21430665813919 is an apocalyptic number.

1430665813919 is a deficient number, since it is larger than the sum of its proper divisors (1).

1430665813919 is an equidigital number, since it uses as much as digits as its factorization.

1430665813919 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4199040, while the sum is 56.

The spelling of 1430665813919 in words is "one trillion, four hundred thirty billion, six hundred sixty-five million, eight hundred thirteen thousand, nine hundred nineteen".