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143101241 is a prime number
BaseRepresentation
bin10001000011110…
…00110100111001
3100222021021222222
420201320310321
5243113214431
622111053425
73355224533
oct1041706471
9328237888
10143101241
1173860098
123bb11275
1323854aba
1415010853
15c86a57b
hex8878d39

143101241 has 2 divisors, whose sum is σ = 143101242. Its totient is φ = 143101240.

The previous prime is 143101199. The next prime is 143101271. The reversal of 143101241 is 142101341.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80928016 + 62173225 = 8996^2 + 7885^2 .

It is a cyclic number.

It is not a de Polignac number, because 143101241 - 214 = 143084857 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (143101271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71550620 + 71550621.

It is an arithmetic number, because the mean of its divisors is an integer number (71550621).

Almost surely, 2143101241 is an apocalyptic number.

It is an amenable number.

143101241 is a deficient number, since it is larger than the sum of its proper divisors (1).

143101241 is an equidigital number, since it uses as much as digits as its factorization.

143101241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 143101241 is about 11962.4930929970. The cubic root of 143101241 is about 523.0555323948.

Adding to 143101241 its reverse (142101341), we get a palindrome (285202582).

It can be divided in two parts, 14310 and 1241, that added together give a palindrome (15551).

The spelling of 143101241 in words is "one hundred forty-three million, one hundred one thousand, two hundred forty-one".