Base | Representation |
---|---|
bin | 1101000000111101010111… |
… | …1011010010001110100111 |
3 | 1212200000221020002221201112 |
4 | 3100033111323102032213 |
5 | 3333424114014314033 |
6 | 50233551501215235 |
7 | 3004605145552133 |
oct | 320172573221647 |
9 | 55600836087645 |
10 | 14310125151143 |
11 | 4617987646898 |
12 | 1731493b6151b |
13 | 7ca59267b743 |
14 | 3768841d03c3 |
15 | 19c38c43bc48 |
hex | d03d5ed23a7 |
14310125151143 has 2 divisors, whose sum is σ = 14310125151144. Its totient is φ = 14310125151142.
The previous prime is 14310125151109. The next prime is 14310125151163. The reversal of 14310125151143 is 34115152101341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14310125151143 - 220 = 14310124102567 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14310125151163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155062575571 + 7155062575572.
It is an arithmetic number, because the mean of its divisors is an integer number (7155062575572).
Almost surely, 214310125151143 is an apocalyptic number.
14310125151143 is a deficient number, since it is larger than the sum of its proper divisors (1).
14310125151143 is an equidigital number, since it uses as much as digits as its factorization.
14310125151143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 32.
Adding to 14310125151143 its reverse (34115152101341), we get a palindrome (48425277252484).
The spelling of 14310125151143 in words is "fourteen trillion, three hundred ten billion, one hundred twenty-five million, one hundred fifty-one thousand, one hundred forty-three".
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