143101443101 has 2 divisors, whose sum is σ = 143101443102. Its totient is φ = 143101443100.

The previous prime is 143101443049. The next prime is 143101443103. The reversal of 143101443101 is 101344101341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 138570807001 + 4530636100 = 372251^2 + 67310^2 .

It is a cyclic number.

It is not a de Polignac number, because 143101443101 - 2²² = 143097248797 is a prime.

Together with 143101443103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143101443103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71550721550 + 71550721551.

It is an arithmetic number, because the mean of its divisors is an integer number (71550721551).

Almost surely, 2^143101443101 is an apocalyptic number.

It is an amenable number.

143101443101 is a deficient number, since it is larger than the sum of its proper divisors (1).

143101443101 is an equidigital number, since it uses as much as digits as its factorization.

143101443101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 143101443101 its reverse (101344101341), we get a palindrome (244445544442).

The spelling of 143101443101 in words is "one hundred forty-three billion, one hundred one million, four hundred forty-three thousand, one hundred one".