1431020114 has 4 divisors (see below), whose sum is σ = 2146530174. Its totient is φ = 715510056.

The previous prime is 1431020113. The next prime is 1431020119. The reversal of 1431020114 is 4110201341.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 4110201341 = 5407 ⋅760163.

It can be written as a sum of positive squares in only one way, i.e., 829152025 + 601868089 = 28795^2 + 24533^2 .

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1431020092 and 1431020101.

It is not an unprimeable number, because it can be changed into a prime (1431020111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 357755027 + ... + 357755030.

Almost surely, 2^1431020114 is an apocalyptic number.

1431020114 is a deficient number, since it is larger than the sum of its proper divisors (715510060).

1431020114 is an equidigital number, since it uses as much as digits as its factorization.

1431020114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 715510059.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 1431020114 is about 37828.8264951479. The cubic root of 1431020114 is about 1126.8910060411.

Adding to 1431020114 its reverse (4110201341), we get a palindrome (5541221455).

The spelling of 1431020114 in words is "one billion, four hundred thirty-one million, twenty thousand, one hundred fourteen".