Base | Representation |
---|---|
bin | 1000010101000110011… |
… | …1011110101001010001 |
3 | 111200101002222000100021 |
4 | 2011101213132221101 |
5 | 4321033411140101 |
6 | 145423554423441 |
7 | 13224142223524 |
oct | 2052147365121 |
9 | 450332860307 |
10 | 143103224401 |
11 | 55765048605 |
12 | 23898b91b81 |
13 | 10657778857 |
14 | 6cd7824bbb |
15 | 3ac83a55a1 |
hex | 21519dea51 |
143103224401 has 2 divisors, whose sum is σ = 143103224402. Its totient is φ = 143103224400.
The previous prime is 143103224399. The next prime is 143103224417. The reversal of 143103224401 is 104422301341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 90948083776 + 52155140625 = 301576^2 + 228375^2 .
It is a cyclic number.
It is not a de Polignac number, because 143103224401 - 21 = 143103224399 is a prime.
Together with 143103224399, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (143103224501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71551612200 + 71551612201.
It is an arithmetic number, because the mean of its divisors is an integer number (71551612201).
Almost surely, 2143103224401 is an apocalyptic number.
It is an amenable number.
143103224401 is a deficient number, since it is larger than the sum of its proper divisors (1).
143103224401 is an equidigital number, since it uses as much as digits as its factorization.
143103224401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 143103224401 its reverse (104422301341), we get a palindrome (247525525742).
The spelling of 143103224401 in words is "one hundred forty-three billion, one hundred three million, two hundred twenty-four thousand, four hundred one".
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