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14310425230 = 251431042523
BaseRepresentation
bin11010101001111011…
…11100001010001110
31100221022120220221021
431110331330022032
5213301432101410
610324002024354
71014424415233
oct152475741216
940838526837
1014310425230
116083953312
1229346480ba
131470a19c4a
1499a80178a
1558b500eda
hex354f7c28e

14310425230 has 8 divisors (see below), whose sum is σ = 25758765432. Its totient is φ = 5724170088.

The previous prime is 14310425221. The next prime is 14310425243. The reversal of 14310425230 is 3252401341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 14310425195 and 14310425204.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 715521252 + ... + 715521271.

It is an arithmetic number, because the mean of its divisors is an integer number (3219845679).

Almost surely, 214310425230 is an apocalyptic number.

14310425230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14310425230 is a deficient number, since it is larger than the sum of its proper divisors (11448340202).

14310425230 is a wasteful number, since it uses less digits than its factorization.

14310425230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1431042530.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 14310425230 its reverse (3252401341), we get a palindrome (17562826571).

The spelling of 14310425230 in words is "fourteen billion, three hundred ten million, four hundred twenty-five thousand, two hundred thirty".

Divisors: 1 2 5 10 1431042523 2862085046 7155212615 14310425230