Base | Representation |
---|---|
bin | 101010101001100… |
… | …0100111010100111 |
3 | 10200201210121001221 |
4 | 1111103010322213 |
5 | 10412323023411 |
6 | 354000401211 |
7 | 50314562632 |
oct | 12523047247 |
9 | 3621717057 |
10 | 1431064231 |
11 | 674886813 |
12 | 33b316207 |
13 | 19a636c8c |
14 | d80bac19 |
15 | 8597e071 |
hex | 554c4ea7 |
1431064231 has 2 divisors, whose sum is σ = 1431064232. Its totient is φ = 1431064230.
The previous prime is 1431064213. The next prime is 1431064259. The reversal of 1431064231 is 1324601341.
Together with previous prime (1431064213) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1431064231 - 29 = 1431063719 is a prime.
It is a super-2 number, since 2×14310642312 = 4095889666495242722, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1431064196 and 1431064205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1431064031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715532115 + 715532116.
It is an arithmetic number, because the mean of its divisors is an integer number (715532116).
Almost surely, 21431064231 is an apocalyptic number.
1431064231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1431064231 is an equidigital number, since it uses as much as digits as its factorization.
1431064231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
The square root of 1431064231 is about 37829.4096041691. The cubic root of 1431064231 is about 1126.9025862510.
Adding to 1431064231 its reverse (1324601341), we get a palindrome (2755665572).
The spelling of 1431064231 in words is "one billion, four hundred thirty-one million, sixty-four thousand, two hundred thirty-one".
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