14311121131 has 2 divisors, whose sum is σ = 14311121132. Its totient is φ = 14311121130.

The previous prime is 14311121117. The next prime is 14311121147. The reversal of 14311121131 is 13112111341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14311121131 - 2¹¹ = 14311119083 is a prime.

It is a super-2 number, since 2×14311121131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14311121099 and 14311121108.

It is not a weakly prime, because it can be changed into another prime (14311121171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155560565 + 7155560566.

It is an arithmetic number, because the mean of its divisors is an integer number (7155560566).

Almost surely, 2^14311121131 is an apocalyptic number.

14311121131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14311121131 is an equidigital number, since it uses as much as digits as its factorization.

14311121131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 72, while the sum is 19.

Adding to 14311121131 its reverse (13112111341), we get a palindrome (27423232472).

The spelling of 14311121131 in words is "fourteen billion, three hundred eleven million, one hundred twenty-one thousand, one hundred thirty-one".