14311121117 has 2 divisors, whose sum is σ = 14311121118. Its totient is φ = 14311121116.

The previous prime is 14311121093. The next prime is 14311121131. The reversal of 14311121117 is 71112111341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12530787481 + 1780333636 = 111941^2 + 42194^2 .

It is a cyclic number.

It is not a de Polignac number, because 14311121117 - 2⁸ = 14311120861 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14311121092 and 14311121101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14311121147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155560558 + 7155560559.

It is an arithmetic number, because the mean of its divisors is an integer number (7155560559).

Almost surely, 2^14311121117 is an apocalyptic number.

It is an amenable number.

14311121117 is a deficient number, since it is larger than the sum of its proper divisors (1).

14311121117 is an equidigital number, since it uses as much as digits as its factorization.

14311121117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 168, while the sum is 23.

Adding to 14311121117 its reverse (71112111341), we get a palindrome (85423232458).

The spelling of 14311121117 in words is "fourteen billion, three hundred eleven million, one hundred twenty-one thousand, one hundred seventeen".