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14311121147 is a prime number
BaseRepresentation
bin11010101010000001…
…00110000011111011
31100221100220021112222
431111000212003323
5213302121334042
610324024554255
71014433344161
oct152500460373
940840807488
1014311121147
116084289154
12293492298b
131470c0192b
1499a943231
1558b5dc2d2
hex3550260fb

14311121147 has 2 divisors, whose sum is σ = 14311121148. Its totient is φ = 14311121146.

The previous prime is 14311121131. The next prime is 14311121159. The reversal of 14311121147 is 74112111341.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14311121147 - 24 = 14311121131 is a prime.

It is a super-2 number, since 2×143111211472 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14311121117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155560573 + 7155560574.

It is an arithmetic number, because the mean of its divisors is an integer number (7155560574).

Almost surely, 214311121147 is an apocalyptic number.

14311121147 is a deficient number, since it is larger than the sum of its proper divisors (1).

14311121147 is an equidigital number, since it uses as much as digits as its factorization.

14311121147 is an evil number, because the sum of its binary digits is even.

The product of its digits is 672, while the sum is 26.

Adding to 14311121147 its reverse (74112111341), we get a palindrome (88423232488).

The spelling of 14311121147 in words is "fourteen billion, three hundred eleven million, one hundred twenty-one thousand, one hundred forty-seven".