1431121313000 has 64 divisors (see below), whose sum is σ = 3426703600320. Its totient is φ = 559135752000.

The previous prime is 1431121312987. The next prime is 1431121313003. The reversal of 1431121313000 is 3131211341.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is not an unprimeable number, because it can be changed into a prime (1431121313003) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16597946 + ... + 16683945.

It is an arithmetic number, because the mean of its divisors is an integer number (53542243755).

Almost surely, 2^{1431121313000} is an apocalyptic number.

1431121313000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1431121313000 is an abundant number, since it is smaller than the sum of its proper divisors (1995582287320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1431121313000 is a wasteful number, since it uses less digits than its factorization.

1431121313000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33281955 (or 33281941 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 1431121313000 its reverse (3131211341), we get a palindrome (1434252524341).

The spelling of 1431121313000 in words is "one trillion, four hundred thirty-one billion, one hundred twenty-one million, three hundred thirteen thousand".