Base | Representation |
---|---|
bin | 11010101010000001… |
… | …11110110010110111 |
3 | 1100221101002102112010 |
4 | 31111000332302313 |
5 | 213302133104310 |
6 | 10324031055303 |
7 | 1014434245425 |
oct | 152500766267 |
9 | 40841072463 |
10 | 14311222455 |
11 | 6084348282 |
12 | 2934971533 |
13 | 1470c38a8a |
14 | 99a96c115 |
15 | 58b60c320 |
hex | 35503ecb7 |
14311222455 has 32 divisors (see below), whose sum is σ = 24261120000. Its totient is φ = 7178865152.
The previous prime is 14311222411. The next prime is 14311222459. The reversal of 14311222455 is 55422211341.
It is a cyclic number.
It is not a de Polignac number, because 14311222455 - 214 = 14311206071 is a prime.
It is a super-2 number, since 2×143112224552 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14311222459) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 379546 + ... + 415544.
It is an arithmetic number, because the mean of its divisors is an integer number (758160000).
Almost surely, 214311222455 is an apocalyptic number.
14311222455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14311222455 is a deficient number, since it is larger than the sum of its proper divisors (9949897545).
14311222455 is a wasteful number, since it uses less digits than its factorization.
14311222455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37583.
The product of its digits is 9600, while the sum is 30.
Adding to 14311222455 its reverse (55422211341), we get a palindrome (69733433796).
The spelling of 14311222455 in words is "fourteen billion, three hundred eleven million, two hundred twenty-two thousand, four hundred fifty-five".
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