Base | Representation |
---|---|
bin | 1101000001000001110101… |
… | …0101100111000000100111 |
3 | 1212200011000201111212220101 |
4 | 3100100131111213000213 |
5 | 3333434042221444333 |
6 | 50234310420244531 |
7 | 3004646634235102 |
oct | 320203525470047 |
9 | 55604021455811 |
10 | 14311323234343 |
11 | 46184419634a3 |
12 | 1731769240747 |
13 | 7ca723951605 |
14 | 376959381739 |
15 | 19c40c6e967d |
hex | d041d567027 |
14311323234343 has 2 divisors, whose sum is σ = 14311323234344. Its totient is φ = 14311323234342.
The previous prime is 14311323234289. The next prime is 14311323234391. The reversal of 14311323234343 is 34343232311341.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14311323234343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14311323234443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155661617171 + 7155661617172.
It is an arithmetic number, because the mean of its divisors is an integer number (7155661617172).
Almost surely, 214311323234343 is an apocalyptic number.
14311323234343 is a deficient number, since it is larger than the sum of its proper divisors (1).
14311323234343 is an equidigital number, since it uses as much as digits as its factorization.
14311323234343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 186624, while the sum is 37.
Adding to 14311323234343 its reverse (34343232311341), we get a palindrome (48654555545684).
The spelling of 14311323234343 in words is "fourteen trillion, three hundred eleven billion, three hundred twenty-three million, two hundred thirty-four thousand, three hundred forty-three".
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