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14311323234343 is a prime number
BaseRepresentation
bin1101000001000001110101…
…0101100111000000100111
31212200011000201111212220101
43100100131111213000213
53333434042221444333
650234310420244531
73004646634235102
oct320203525470047
955604021455811
1014311323234343
1146184419634a3
121731769240747
137ca723951605
14376959381739
1519c40c6e967d
hexd041d567027

14311323234343 has 2 divisors, whose sum is σ = 14311323234344. Its totient is φ = 14311323234342.

The previous prime is 14311323234289. The next prime is 14311323234391. The reversal of 14311323234343 is 34343232311341.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14311323234343 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14311323234443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155661617171 + 7155661617172.

It is an arithmetic number, because the mean of its divisors is an integer number (7155661617172).

Almost surely, 214311323234343 is an apocalyptic number.

14311323234343 is a deficient number, since it is larger than the sum of its proper divisors (1).

14311323234343 is an equidigital number, since it uses as much as digits as its factorization.

14311323234343 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 186624, while the sum is 37.

Adding to 14311323234343 its reverse (34343232311341), we get a palindrome (48654555545684).

The spelling of 14311323234343 in words is "fourteen trillion, three hundred eleven billion, three hundred twenty-three million, two hundred thirty-four thousand, three hundred forty-three".