Base | Representation |
---|---|
bin | 1101000001000001110101… |
… | …0101100111000001010111 |
3 | 1212200011000201111212222011 |
4 | 3100100131111213001113 |
5 | 3333434042222000031 |
6 | 50234310420245051 |
7 | 3004646634235201 |
oct | 320203525470127 |
9 | 55604021455864 |
10 | 14311323234391 |
11 | 4618441963537 |
12 | 1731769240787 |
13 | 7ca723951641 |
14 | 376959381771 |
15 | 19c40c6e96b1 |
hex | d041d567057 |
14311323234391 has 2 divisors, whose sum is σ = 14311323234392. Its totient is φ = 14311323234390.
The previous prime is 14311323234343. The next prime is 14311323234431. The reversal of 14311323234391 is 19343232311341.
It is an a-pointer prime, because the next prime (14311323234431) can be obtained adding 14311323234391 to its sum of digits (40).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14311323234391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14311323264391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7155661617195 + 7155661617196.
It is an arithmetic number, because the mean of its divisors is an integer number (7155661617196).
Almost surely, 214311323234391 is an apocalyptic number.
14311323234391 is a deficient number, since it is larger than the sum of its proper divisors (1).
14311323234391 is an equidigital number, since it uses as much as digits as its factorization.
14311323234391 is an evil number, because the sum of its binary digits is even.
The product of its digits is 139968, while the sum is 40.
The spelling of 14311323234391 in words is "fourteen trillion, three hundred eleven billion, three hundred twenty-three million, two hundred thirty-four thousand, three hundred ninety-one".
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