14312030000 has 50 divisors (see below), whose sum is σ = 34650880044. Its totient is φ = 5724808000.

The previous prime is 14312029969. The next prime is 14312030011. The reversal of 14312030000 is 3021341.

It is a tau number, because it is divible by the number of its divisors (50).

It is an unprimeable number.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 705602 + ... + 725601.

Almost surely, 2^14312030000 is an apocalyptic number.

14312030000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14312030000 is an abundant number, since it is smaller than the sum of its proper divisors (20338850044).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14312030000 is an equidigital number, since it uses as much as digits as its factorization.

14312030000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1431231 (or 1431210 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 14312030000 its reverse (3021341), we get a palindrome (14315051341).

The spelling of 14312030000 in words is "fourteen billion, three hundred twelve million, thirty thousand".