Base | Representation |
---|---|
bin | 1000010101001010101… |
… | …1011010001100111101 |
3 | 111200102100110201202212 |
4 | 2011102223122030331 |
5 | 4321102441010442 |
6 | 145425432230205 |
7 | 13224446461646 |
oct | 2052253321475 |
9 | 450370421685 |
10 | 143121031997 |
11 | 55774100729 |
12 | 238a2b3b365 |
13 | 1065b3720a8 |
14 | 6cd9d3c6cd |
15 | 3ac9c21a82 |
hex | 2152ada33d |
143121031997 has 2 divisors, whose sum is σ = 143121031998. Its totient is φ = 143121031996.
The previous prime is 143121031969. The next prime is 143121032053. The reversal of 143121031997 is 799130121341.
143121031997 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 107314552921 + 35806479076 = 327589^2 + 189226^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-143121031997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143121036997) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71560515998 + 71560515999.
It is an arithmetic number, because the mean of its divisors is an integer number (71560515999).
Almost surely, 2143121031997 is an apocalyptic number.
It is an amenable number.
143121031997 is a deficient number, since it is larger than the sum of its proper divisors (1).
143121031997 is an equidigital number, since it uses as much as digits as its factorization.
143121031997 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40824, while the sum is 41.
The spelling of 143121031997 in words is "one hundred forty-three billion, one hundred twenty-one million, thirty-one thousand, nine hundred ninety-seven".
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