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143121032053 is a prime number
BaseRepresentation
bin1000010101001010101…
…1011010001101110101
3111200102100110201211221
42011102223122031311
54321102441011203
6145425432230341
713224446462056
oct2052253321565
9450370421757
10143121032053
115577410077a
12238a2b3b3b1
131065b37211c
146cd9d3c72d
153ac9c21abd
hex2152ada375

143121032053 has 2 divisors, whose sum is σ = 143121032054. Its totient is φ = 143121032052.

The previous prime is 143121031997. The next prime is 143121032057. The reversal of 143121032053 is 350230121341.

It is a happy number.

143121032053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129947272324 + 13173759729 = 360482^2 + 114777^2 .

It is a cyclic number.

It is not a de Polignac number, because 143121032053 - 29 = 143121031541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143121032057) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71560516026 + 71560516027.

It is an arithmetic number, because the mean of its divisors is an integer number (71560516027).

Almost surely, 2143121032053 is an apocalyptic number.

It is an amenable number.

143121032053 is a deficient number, since it is larger than the sum of its proper divisors (1).

143121032053 is an equidigital number, since it uses as much as digits as its factorization.

143121032053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 143121032053 its reverse (350230121341), we get a palindrome (493351153394).

The spelling of 143121032053 in words is "one hundred forty-three billion, one hundred twenty-one million, thirty-two thousand, fifty-three".