143121303341 has 2 divisors, whose sum is σ = 143121303342. Its totient is φ = 143121303340.

The previous prime is 143121303317. The next prime is 143121303343. The reversal of 143121303341 is 143303121341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 139611333316 + 3509970025 = 373646^2 + 59245^2 .

It is a cyclic number.

It is not a de Polignac number, because 143121303341 - 2⁶ = 143121303277 is a prime.

Together with 143121303343, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 143121303341.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143121303343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71560651670 + 71560651671.

It is an arithmetic number, because the mean of its divisors is an integer number (71560651671).

Almost surely, 2^143121303341 is an apocalyptic number.

It is an amenable number.

143121303341 is a deficient number, since it is larger than the sum of its proper divisors (1).

143121303341 is an equidigital number, since it uses as much as digits as its factorization.

143121303341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 143121303341 its reverse (143303121341), we get a palindrome (286424424682).

The spelling of 143121303341 in words is "one hundred forty-three billion, one hundred twenty-one million, three hundred three thousand, three hundred forty-one".