1431214111 has 2 divisors, whose sum is σ = 1431214112. Its totient is φ = 1431214110.

The previous prime is 1431214093. The next prime is 1431214117. The reversal of 1431214111 is 1114121341.

It is a strong prime.

It is an emirp because it is prime and its reverse (1114121341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1431214111 - 2⁵ = 1431214079 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1431214117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715607055 + 715607056.

It is an arithmetic number, because the mean of its divisors is an integer number (715607056).

Almost surely, 2^1431214111 is an apocalyptic number.

1431214111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431214111 is an equidigital number, since it uses as much as digits as its factorization.

1431214111 is an evil number, because the sum of its binary digits is even.

The product of its digits is 96, while the sum is 19.

The square root of 1431214111 is about 37831.3905507054. The cubic root of 1431214111 is about 1126.9419262656.

Adding to 1431214111 its reverse (1114121341), we get a palindrome (2545335452).

The spelling of 1431214111 in words is "one billion, four hundred thirty-one million, two hundred fourteen thousand, one hundred eleven".