Base | Representation |
---|---|
bin | 1101000001000100111100… |
… | …1110001001101101010111 |
3 | 1212200020012001022002210121 |
4 | 3100101033032021231113 |
5 | 3333442300443440434 |
6 | 50234525434132411 |
7 | 3005006445641452 |
oct | 320211716115527 |
9 | 55606161262717 |
10 | 14312160140119 |
11 | 4618831311166 |
12 | 1731961581107 |
13 | 7ca82815682a |
14 | 3769d8596499 |
15 | 19c45ae117b4 |
hex | d044f389b57 |
14312160140119 has 2 divisors, whose sum is σ = 14312160140120. Its totient is φ = 14312160140118.
The previous prime is 14312160140063. The next prime is 14312160140141. The reversal of 14312160140119 is 91104106121341.
14312160140119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14312160140119 - 215 = 14312160107351 is a prime.
It is a super-2 number, since 2×143121601401192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14312160143119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156080070059 + 7156080070060.
It is an arithmetic number, because the mean of its divisors is an integer number (7156080070060).
Almost surely, 214312160140119 is an apocalyptic number.
14312160140119 is a deficient number, since it is larger than the sum of its proper divisors (1).
14312160140119 is an equidigital number, since it uses as much as digits as its factorization.
14312160140119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 34.
The spelling of 14312160140119 in words is "fourteen trillion, three hundred twelve billion, one hundred sixty million, one hundred forty thousand, one hundred nineteen".
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