1431218812847 has 2 divisors, whose sum is σ = 1431218812848. Its totient is φ = 1431218812846.

The previous prime is 1431218812813. The next prime is 1431218812897. The reversal of 1431218812847 is 7482188121341.

It is an a-pointer prime, because the next prime (1431218812897) can be obtained adding 1431218812847 to its sum of digits (50).

It is a weak prime.

It is an emirp because it is prime and its reverse (7482188121341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1431218812847 - 2⁶ = 1431218812783 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1431218812795 and 1431218812804.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1431218812897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715609406423 + 715609406424.

It is an arithmetic number, because the mean of its divisors is an integer number (715609406424).

Almost surely, 2^{1431218812847} is an apocalyptic number.

1431218812847 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431218812847 is an equidigital number, since it uses as much as digits as its factorization.

1431218812847 is an evil number, because the sum of its binary digits is even.

The product of its digits is 688128, while the sum is 50.

The spelling of 1431218812847 in words is "one trillion, four hundred thirty-one billion, two hundred eighteen million, eight hundred twelve thousand, eight hundred forty-seven".