Base | Representation |
---|---|
bin | 11010101010001001… |
… | …10101000101000001 |
3 | 1100221102222200022021 |
4 | 31111010311011001 |
5 | 213302412344413 |
6 | 10324104441441 |
7 | 1014445646446 |
oct | 152504650501 |
9 | 40842880267 |
10 | 14312231233 |
11 | 6084977183 |
12 | 2935179281 |
13 | 14711ccca1 |
14 | 99ab519cd |
15 | 58b75b18d |
hex | 355135141 |
14312231233 has 2 divisors, whose sum is σ = 14312231234. Its totient is φ = 14312231232.
The previous prime is 14312231231. The next prime is 14312231237. The reversal of 14312231233 is 33213221341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13144163904 + 1168067329 = 114648^2 + 34177^2 .
It is a cyclic number.
It is not a de Polignac number, because 14312231233 - 21 = 14312231231 is a prime.
Together with 14312231231, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 14312231198 and 14312231207.
It is not a weakly prime, because it can be changed into another prime (14312231231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156115616 + 7156115617.
It is an arithmetic number, because the mean of its divisors is an integer number (7156115617).
Almost surely, 214312231233 is an apocalyptic number.
It is an amenable number.
14312231233 is a deficient number, since it is larger than the sum of its proper divisors (1).
14312231233 is an equidigital number, since it uses as much as digits as its factorization.
14312231233 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2592, while the sum is 25.
Adding to 14312231233 its reverse (33213221341), we get a palindrome (47525452574).
The spelling of 14312231233 in words is "fourteen billion, three hundred twelve million, two hundred thirty-one thousand, two hundred thirty-three".
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