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14312344253 is a prime number
BaseRepresentation
bin11010101010001010…
…10000101010111101
31100221110012102100012
431111011100222331
5213302430004003
610324111113005
71014446630114
oct152505205275
940843172305
1014312344253
116084a44089
122935212765
13147123c56c
1499ab80c7b
1558b77e8d8
hex355150abd

14312344253 has 2 divisors, whose sum is σ = 14312344254. Its totient is φ = 14312344252.

The previous prime is 14312344237. The next prime is 14312344309. The reversal of 14312344253 is 35244321341.

14312344253 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12091861369 + 2220482884 = 109963^2 + 47122^2 .

It is a cyclic number.

It is not a de Polignac number, because 14312344253 - 24 = 14312344237 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14312344853) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156172126 + 7156172127.

It is an arithmetic number, because the mean of its divisors is an integer number (7156172127).

Almost surely, 214312344253 is an apocalyptic number.

It is an amenable number.

14312344253 is a deficient number, since it is larger than the sum of its proper divisors (1).

14312344253 is an equidigital number, since it uses as much as digits as its factorization.

14312344253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 34560, while the sum is 32.

Adding to 14312344253 its reverse (35244321341), we get a palindrome (49556665594).

The spelling of 14312344253 in words is "fourteen billion, three hundred twelve million, three hundred forty-four thousand, two hundred fifty-three".