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143124052521449 is a prime number
BaseRepresentation
bin100000100010101110101010…
…010011110011000111101001
3200202202112012022012211212202
4200202232222103303013221
5122224421024421141244
61224222140530345545
742101241305420666
oct4042565223630751
9622675168184782
10143124052521449
114167062a45941a
121407649772b2b5
1361b2703ba833c
14274b353832a6d
151182eb988304e
hex822baa4f31e9

143124052521449 has 2 divisors, whose sum is σ = 143124052521450. Its totient is φ = 143124052521448.

The previous prime is 143124052521403. The next prime is 143124052521467. The reversal of 143124052521449 is 944125250421341.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87679945155049 + 55444107366400 = 9363757^2 + 7446080^2 .

It is a cyclic number.

It is not a de Polignac number, because 143124052521449 - 236 = 143055333044713 is a prime.

It is not a weakly prime, because it can be changed into another prime (143124052526449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71562026260724 + 71562026260725.

It is an arithmetic number, because the mean of its divisors is an integer number (71562026260725).

Almost surely, 2143124052521449 is an apocalyptic number.

It is an amenable number.

143124052521449 is a deficient number, since it is larger than the sum of its proper divisors (1).

143124052521449 is an equidigital number, since it uses as much as digits as its factorization.

143124052521449 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1382400, while the sum is 47.

The spelling of 143124052521449 in words is "one hundred forty-three trillion, one hundred twenty-four billion, fifty-two million, five hundred twenty-one thousand, four hundred forty-nine".