Base | Representation |
---|---|
bin | 1101000001000101111101… |
… | …1111111000000111110100 |
3 | 1212200020220002011002220020 |
4 | 3100101133133320013310 |
5 | 3333443330401102012 |
6 | 50235012511205140 |
7 | 3005016303050103 |
oct | 320213737700764 |
9 | 55606802132806 |
10 | 14312433222132 |
11 | 461896147a781 |
12 | 1731a18b167b0 |
13 | 7ca86c8bb416 |
14 | 376a2296003a |
15 | 19c474da4a8c |
hex | d045f7f81f4 |
14312433222132 has 36 divisors (see below), whose sum is σ = 35475685123200. Its totient is φ = 4490175127424.
The previous prime is 14312433221953. The next prime is 14312433222179. The reversal of 14312433222132 is 23122233421341.
It is a happy number.
It is a nude number because it is divisible by every one of its digits.
It is a junction number, because it is equal to n+sod(n) for n = 14312433222093 and 14312433222102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2063496132 + ... + 2063503067.
Almost surely, 214312433222132 is an apocalyptic number.
14312433222132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
14312433222132 is an abundant number, since it is smaller than the sum of its proper divisors (21163251901068).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14312433222132 is a wasteful number, since it uses less digits than its factorization.
14312433222132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4126999240 (or 4126999221 counting only the distinct ones).
The product of its digits is 41472, while the sum is 33.
Adding to 14312433222132 its reverse (23122233421341), we get a palindrome (37434666643473).
The spelling of 14312433222132 in words is "fourteen trillion, three hundred twelve billion, four hundred thirty-three million, two hundred twenty-two thousand, one hundred thirty-two".
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