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1431244097 is a prime number
BaseRepresentation
bin101010101001111…
…0000110101000001
310200202010201210122
41111103300311001
510412344302342
6354004310025
750316242213
oct12523606501
93622121718
101431244097
11674999968
1233b3a2315
1319a69aaca
14d81265b3
15859b74d2
hex554f0d41

1431244097 has 2 divisors, whose sum is σ = 1431244098. Its totient is φ = 1431244096.

The previous prime is 1431244079. The next prime is 1431244099. The reversal of 1431244097 is 7904421341.

It is a happy number.

Together with previous prime (1431244079) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1431184561 + 59536 = 37831^2 + 244^2 .

It is a cyclic number.

It is not a de Polignac number, because 1431244097 - 28 = 1431243841 is a prime.

Together with 1431244099, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1431244099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715622048 + 715622049.

It is an arithmetic number, because the mean of its divisors is an integer number (715622049).

Almost surely, 21431244097 is an apocalyptic number.

It is an amenable number.

1431244097 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431244097 is an equidigital number, since it uses as much as digits as its factorization.

1431244097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24192, while the sum is 35.

The square root of 1431244097 is about 37831.7868597295. The cubic root of 1431244097 is about 1126.9497965636.

The spelling of 1431244097 in words is "one billion, four hundred thirty-one million, two hundred forty-four thousand, ninety-seven".