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1431251401325 = 52471218086299
BaseRepresentation
bin10100110100111101001…
…110110011101001101101
312001211022101000110202012
4110310331032303221231
5141422200324320300
63013301404411005
7205255513116164
oct24647516635155
95054271013665
101431251401325
11501a99115699
121b1477246a65
13a4c7431c615
144d3b6d243db
152736ba79435
hex14d3d3b3a6d

1431251401325 has 12 divisors (see below), whose sum is σ = 1812512414400. Its totient is φ = 1120639394160.

The previous prime is 1431251401297. The next prime is 1431251401357. The reversal of 1431251401325 is 5231041521341.

It is not a de Polignac number, because 1431251401325 - 218 = 1431251139181 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1431251401291 and 1431251401300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 609041975 + ... + 609044324.

It is an arithmetic number, because the mean of its divisors is an integer number (151042701200).

Almost surely, 21431251401325 is an apocalyptic number.

It is an amenable number.

1431251401325 is a deficient number, since it is larger than the sum of its proper divisors (381261013075).

1431251401325 is a wasteful number, since it uses less digits than its factorization.

1431251401325 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1218086356 (or 1218086351 counting only the distinct ones).

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 1431251401325 its reverse (5231041521341), we get a palindrome (6662292922666).

The spelling of 1431251401325 in words is "one trillion, four hundred thirty-one billion, two hundred fifty-one million, four hundred one thousand, three hundred twenty-five".

Divisors: 1 5 25 47 235 1175 1218086299 6090431495 30452157475 57250056053 286250280265 1431251401325