Base | Representation |
---|---|
bin | 1000010101001011111… |
… | …1001000011101101111 |
3 | 111200102201012101222201 |
4 | 2011102333020131233 |
5 | 4321110301432343 |
6 | 145430135122331 |
7 | 13224541434334 |
oct | 2052277103557 |
9 | 450381171881 |
10 | 143126202223 |
11 | 55777012144 |
12 | 238a48133a7 |
13 | 1065c4624b4 |
14 | 6cda8c698b |
15 | 3aca3e394d |
hex | 2152fc876f |
143126202223 has 2 divisors, whose sum is σ = 143126202224. Its totient is φ = 143126202222.
The previous prime is 143126202217. The next prime is 143126202251. The reversal of 143126202223 is 322202621341.
It is an a-pointer prime, because the next prime (143126202251) can be obtained adding 143126202223 to its sum of digits (28).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 143126202223 - 29 = 143126201711 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 143126202191 and 143126202200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143126202823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71563101111 + 71563101112.
It is an arithmetic number, because the mean of its divisors is an integer number (71563101112).
Almost surely, 2143126202223 is an apocalyptic number.
143126202223 is a deficient number, since it is larger than the sum of its proper divisors (1).
143126202223 is an equidigital number, since it uses as much as digits as its factorization.
143126202223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 143126202223 its reverse (322202621341), we get a palindrome (465328823564).
The spelling of 143126202223 in words is "one hundred forty-three billion, one hundred twenty-six million, two hundred two thousand, two hundred twenty-three".
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