Base | Representation |
---|---|
bin | 10100110101000000010… |
… | …101010000010101101111 |
3 | 12001211102222220110112121 |
4 | 110311000111100111233 |
5 | 141422302134021333 |
6 | 3013310503413411 |
7 | 205260014234653 |
oct | 24650025202557 |
9 | 5054388813477 |
10 | 1431303423343 |
11 | 5020155175a2 |
12 | 1b1490754267 |
13 | a4c82035191 |
14 | 4d3bdbc6a63 |
15 | 2737140332d |
hex | 14d4055056f |
1431303423343 has 2 divisors, whose sum is σ = 1431303423344. Its totient is φ = 1431303423342.
The previous prime is 1431303423331. The next prime is 1431303423349. The reversal of 1431303423343 is 3433243031341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1431303423343 - 213 = 1431303415151 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1431303423299 and 1431303423308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1431303423349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715651711671 + 715651711672.
It is an arithmetic number, because the mean of its divisors is an integer number (715651711672).
Almost surely, 21431303423343 is an apocalyptic number.
1431303423343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1431303423343 is an equidigital number, since it uses as much as digits as its factorization.
1431303423343 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 34.
Adding to 1431303423343 its reverse (3433243031341), we get a palindrome (4864546454684).
The spelling of 1431303423343 in words is "one trillion, four hundred thirty-one billion, three hundred three million, four hundred twenty-three thousand, three hundred forty-three".
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