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1431310243631 is a prime number
BaseRepresentation
bin10100110101000000101…
…111010001011100101111
312001211110110201222012212
4110311000233101130233
5141422310410244011
63013311305521035
7205260126222122
oct24650057213457
95054413658185
101431310243631
115020193557a4
121b1492aa317b
13a4c83582658
144d3c0a803b9
1527371cee08b
hex14d40bd172f

1431310243631 has 2 divisors, whose sum is σ = 1431310243632. Its totient is φ = 1431310243630.

The previous prime is 1431310243591. The next prime is 1431310243639. The reversal of 1431310243631 is 1363420131341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1431310243631 - 214 = 1431310227247 is a prime.

It is a super-2 number, since 2×14313102436312 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1431310243639) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715655121815 + 715655121816.

It is an arithmetic number, because the mean of its divisors is an integer number (715655121816).

Almost surely, 21431310243631 is an apocalyptic number.

1431310243631 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431310243631 is an equidigital number, since it uses as much as digits as its factorization.

1431310243631 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 32.

Adding to 1431310243631 its reverse (1363420131341), we get a palindrome (2794730374972).

The spelling of 1431310243631 in words is "one trillion, four hundred thirty-one billion, three hundred ten million, two hundred forty-three thousand, six hundred thirty-one".