Base | Representation |
---|---|
bin | 11010101010010000… |
… | …01110011000010100 |
3 | 1100221111122220020201 |
4 | 31111020032120110 |
5 | 213303124340200 |
6 | 10324135510244 |
7 | 1014456344422 |
oct | 152510163024 |
9 | 40844586221 |
10 | 14313121300 |
11 | 6085424975 |
12 | 2935528384 |
13 | 147145215a |
14 | 99ad04112 |
15 | 58b884c6a |
hex | 35520e614 |
14313121300 has 36 divisors (see below), whose sum is σ = 31075816576. Its totient is φ = 5722236000.
The previous prime is 14313121297. The next prime is 14313121301. The reversal of 14313121300 is 312131341.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14313121301) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 158419 + ... + 231781.
Almost surely, 214313121300 is an apocalyptic number.
14313121300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14313121300 is an abundant number, since it is smaller than the sum of its proper divisors (16762695276).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14313121300 is a wasteful number, since it uses less digits than its factorization.
14313121300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75328 (or 75321 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 14313121300 its reverse (312131341), we get a palindrome (14625252641).
The spelling of 14313121300 in words is "fourteen billion, three hundred thirteen million, one hundred twenty-one thousand, three hundred".
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