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143132016315973 is a prime number
BaseRepresentation
bin100000100010110110000100…
…111111010000111001000101
3200202210021202022111112012111
4200202312010333100321011
5122230033332134102343
61224225535054221021
742101642536515556
oct4042660477207105
9622707668445174
10143132016315973
1141673a46848093
1214077b3a7b4771
1361b33a2a82aa9
14274b8ab39432d
1511832d3acac9d
hex822d84fd0e45

143132016315973 has 2 divisors, whose sum is σ = 143132016315974. Its totient is φ = 143132016315972.

The previous prime is 143132016315971. The next prime is 143132016316001. The reversal of 143132016315973 is 379513610231341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 140307270548769 + 2824745767204 = 11845137^2 + 1680698^2 .

It is a cyclic number.

It is not a de Polignac number, because 143132016315973 - 21 = 143132016315971 is a prime.

It is a super-2 number, since 2×1431320163159732 (a number of 29 digits) contains 22 as substring.

Together with 143132016315971, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143132016315971) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71566008157986 + 71566008157987.

It is an arithmetic number, because the mean of its divisors is an integer number (71566008157987).

Almost surely, 2143132016315973 is an apocalyptic number.

It is an amenable number.

143132016315973 is a deficient number, since it is larger than the sum of its proper divisors (1).

143132016315973 is an equidigital number, since it uses as much as digits as its factorization.

143132016315973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1224720, while the sum is 49.

The spelling of 143132016315973 in words is "one hundred forty-three trillion, one hundred thirty-two billion, sixteen million, three hundred fifteen thousand, nine hundred seventy-three".