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14313412130 = 2548712132423
BaseRepresentation
bin11010101010010010…
…10101011000100010
31100221112012200012012
431111021111120202
5213303213142010
610324150032522
71014461665343
oct152511253042
940845180165
1014313412130
116085603426
122935648742
131471524644
1499ad7c0ca
1558b8e1005
hex355255622

14313412130 has 32 divisors (see below), whose sum is σ = 25848993024. Its totient is φ = 5706542016.

The previous prime is 14313412079. The next prime is 14313412153. The reversal of 14313412130 is 3121431341.

It is a super-2 number, since 2×143134121302 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14313412096 and 14313412105.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5906099 + ... + 5908521.

It is an arithmetic number, because the mean of its divisors is an integer number (807781032).

Almost surely, 214313412130 is an apocalyptic number.

14313412130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14313412130 is a deficient number, since it is larger than the sum of its proper divisors (11535580894).

14313412130 is a wasteful number, since it uses less digits than its factorization.

14313412130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4130.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 14313412130 its reverse (3121431341), we get a palindrome (17434843471).

The spelling of 14313412130 in words is "fourteen billion, three hundred thirteen million, four hundred twelve thousand, one hundred thirty".

Divisors: 1 2 5 10 487 974 1213 2423 2426 2435 4846 4870 6065 12115 12130 24230 590731 1180001 1181462 2360002 2939099 2953655 5878198 5900005 5907310 11800010 14695495 29390990 1431341213 2862682426 7156706065 14313412130