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14313413400 = 233521113166823
BaseRepresentation
bin11010101010010010…
…10101101100011000
31100221112012201221020
431111021111230120
5213303213212100
610324150042440
71014462002136
oct152511255430
940845181836
1014313413400
116085604380
122935649420
1314715250b0
1499ad7c756
1558b8e15a0
hex355255b18

14313413400 has 192 divisors, whose sum is σ = 52129163520. Its totient is φ = 3202982400.

The previous prime is 14313413399. The next prime is 14313413419. The reversal of 14313413400 is 431431341.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2389 + ... + 169211.

It is an arithmetic number, because the mean of its divisors is an integer number (271506060).

Almost surely, 214313413400 is an apocalyptic number.

14313413400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14313413400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26064581760).

14313413400 is an abundant number, since it is smaller than the sum of its proper divisors (37815750120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14313413400 is a wasteful number, since it uses less digits than its factorization.

14313413400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 166866 (or 166857 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 14313413400 its reverse (431431341), we get a palindrome (14744844741).

The spelling of 14313413400 in words is "fourteen billion, three hundred thirteen million, four hundred thirteen thousand, four hundred".