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143141101212 = 22311928425101
BaseRepresentation
bin1000010101001111011…
…1111101111010011100
3111200110202020100120010
42011103313331322130
54321123110214322
6145431430323220
713225112166534
oct2052367757234
9450422210503
10143141101212
1155784468a5a
12238a97b9510
131066257ab75
146cdc8844c4
153acb88820c
hex2153dfde9c

143141101212 has 12 divisors (see below), whose sum is σ = 333995902856. Its totient is φ = 47713700400.

The previous prime is 143141101127. The next prime is 143141101253. The reversal of 143141101212 is 212101141341.

It is a tau number, because it is divible by the number of its divisors (12).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5964212539 + ... + 5964212562.

Almost surely, 2143141101212 is an apocalyptic number.

143141101212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

143141101212 is an abundant number, since it is smaller than the sum of its proper divisors (190854801644).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143141101212 is a wasteful number, since it uses less digits than its factorization.

143141101212 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11928425108 (or 11928425106 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 21.

Adding to 143141101212 its reverse (212101141341), we get a palindrome (355242242553).

The spelling of 143141101212 in words is "one hundred forty-three billion, one hundred forty-one million, one hundred one thousand, two hundred twelve".

Divisors: 1 2 3 4 6 12 11928425101 23856850202 35785275303 47713700404 71570550606 143141101212