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143141101127 is a prime number
BaseRepresentation
bin1000010101001111011…
…1111101111001000111
3111200110202020100102222
42011103313331321013
54321123110214002
6145431430322555
713225112166353
oct2052367757107
9450422210388
10143141101127
1155784468992
12238a97b945b
131066257ab0b
146cdc884463
153acb8881a2
hex2153dfde47

143141101127 has 2 divisors, whose sum is σ = 143141101128. Its totient is φ = 143141101126.

The previous prime is 143141101111. The next prime is 143141101253. The reversal of 143141101127 is 721101141341.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 143141101127 - 24 = 143141101111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 143141101096 and 143141101105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143141401127) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71570550563 + 71570550564.

It is an arithmetic number, because the mean of its divisors is an integer number (71570550564).

Almost surely, 2143141101127 is an apocalyptic number.

143141101127 is a deficient number, since it is larger than the sum of its proper divisors (1).

143141101127 is an equidigital number, since it uses as much as digits as its factorization.

143141101127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 672, while the sum is 26.

Adding to 143141101127 its reverse (721101141341), we get a palindrome (864242242468).

The spelling of 143141101127 in words is "one hundred forty-three billion, one hundred forty-one million, one hundred one thousand, one hundred twenty-seven".