Base | Representation |
---|---|
bin | 10100110101001001000… |
… | …101010111111010111010 |
3 | 12001211211020012021202101 |
4 | 110311021011113322322 |
5 | 141423102231130114 |
6 | 3013333230454014 |
7 | 205263446260462 |
oct | 24651105277272 |
9 | 5054736167671 |
10 | 1431450255034 |
11 | 5020903953a8 |
12 | 1b151196430a |
13 | a4ca6594c37 |
14 | 4d3d54c8ba2 |
15 | 2737e258d74 |
hex | 14d49157eba |
1431450255034 has 32 divisors (see below), whose sum is σ = 2191082400000. Its totient is φ = 701132263104.
The previous prime is 1431450255017. The next prime is 1431450255089. The reversal of 1431450255034 is 4305520541341.
It is a junction number, because it is equal to n+sod(n) for n = 1431450254984 and 1431450255002.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 280729017 + ... + 280734115.
It is an arithmetic number, because the mean of its divisors is an integer number (68471325000).
Almost surely, 21431450255034 is an apocalyptic number.
1431450255034 is a deficient number, since it is larger than the sum of its proper divisors (759632144966).
1431450255034 is a wasteful number, since it uses less digits than its factorization.
1431450255034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8742.
The product of its (nonzero) digits is 144000, while the sum is 37.
Adding to 1431450255034 its reverse (4305520541341), we get a palindrome (5736970796375).
The spelling of 1431450255034 in words is "one trillion, four hundred thirty-one billion, four hundred fifty million, two hundred fifty-five thousand, thirty-four".
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