143152441231 has 2 divisors, whose sum is σ = 143152441232. Its totient is φ = 143152441230.

The previous prime is 143152441213. The next prime is 143152441261. The reversal of 143152441231 is 132144251341.

It is a happy number.

143152441231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (143152441213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 143152441231 - 2²⁹ = 142615570319 is a prime.

It is a super-2 number, since 2×143152441231² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 143152441193 and 143152441202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143152441261) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71576220615 + 71576220616.

It is an arithmetic number, because the mean of its divisors is an integer number (71576220616).

Almost surely, 2^143152441231 is an apocalyptic number.

143152441231 is a deficient number, since it is larger than the sum of its proper divisors (1).

143152441231 is an equidigital number, since it uses as much as digits as its factorization.

143152441231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 11520, while the sum is 31.

Adding to 143152441231 its reverse (132144251341), we get a palindrome (275296692572).

The spelling of 143152441231 in words is "one hundred forty-three billion, one hundred fifty-two million, four hundred forty-one thousand, two hundred thirty-one".